Mathematics
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OpenStudy (anonymous):
how to integrate x^2/(1+x^3)
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OpenStudy (anonymous):
i will show you a trick to solve this problem
OpenStudy (anonymous):
Thanks so much
OpenStudy (anonymous):
as you can see the numerator holds the derivative of the denomirator
OpenStudy (anonymous):
the answer would be
OpenStudy (anonymous):
\[\frac{ 1 }{ 3 }\ln(1+x^{3})\]
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OpenStudy (anonymous):
how did this happen?
OpenStudy (anonymous):
The problem is what we're the steps?
OpenStudy (anonymous):
yes i will show you the steps
OpenStudy (anonymous):
but i want you to visualize what is going on
OpenStudy (anonymous):
before i show u the steps
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OpenStudy (anonymous):
Thanks I've been trying or two hours
OpenStudy (anonymous):
please bear in mind a fact in calculus when you see the derivative at the numerator of the denominator then it is a natural log
OpenStudy (anonymous):
please let me know if you don't understand what i mean
OpenStudy (anonymous):
step one: let u = \[(1+x^{3})\]
OpenStudy (anonymous):
Yes I understand
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OpenStudy (anonymous):
step two: d.w.r.x -> \[\frac{ du }{ dx }=3x ^{2}\]
OpenStudy (anonymous):
this means that : \[dx = \frac{ du }{ 3x ^{2} }\]
OpenStudy (anonymous):
Ok so ffar
OpenStudy (anonymous):
step three: look at the main function you are trying to integrate which is : \[\int\limits_{}\frac{ x^2dx }{ 1+x^3 }\]
OpenStudy (anonymous):
now put that in terms of the u
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OpenStudy (anonymous):
\[\int\limits\limits_{}\frac{ x^2du }{ 3x^2u }\]
OpenStudy (anonymous):
now tell me do you see what is going on?
OpenStudy (anonymous):
\[\frac{1}{3}\int\limits\limits\limits_{}\frac{ du }{ u }\]
OpenStudy (anonymous):
Yes so far
OpenStudy (anonymous):
\[\frac{1}{3}\ln (u) + c\]
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OpenStudy (anonymous):
now try yourself to put this last equation in terms of x
OpenStudy (anonymous):
Yes I see it :)
OpenStudy (anonymous):
recall \[\frac{1}{3}\ln (1+x^3) + c\]
OpenStudy (anonymous):
Sorry couldn't type it in right
OpenStudy (anonymous):
so now you should be able to work out by head
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OpenStudy (anonymous):
its ok
OpenStudy (anonymous):
i gave the answer
OpenStudy (anonymous):
Yes I was so confused on how the 1/3 was coming in front of the ln
OpenStudy (anonymous):
I can't thank you enough
OpenStudy (anonymous):
its ok if you have another question i can answer it hopefully
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OpenStudy (anonymous):
you can give me a medal hehehe
OpenStudy (anonymous):
For now that's it , but are you usually online? I might have a question later
OpenStudy (anonymous):
not really not always
OpenStudy (anonymous):
Of course you deserve a hundred medals..just how do I give u one
OpenStudy (anonymous):
i only was here since yesterday but there are others who can help as well
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OpenStudy (anonymous):
i don't know hehehe
OpenStudy (anonymous):
Il find out..ur getting the medal
OpenStudy (anonymous):
thanx that is kind of you
OpenStudy (anonymous):
you are a clever girl you pick up quick the answer
OpenStudy (anonymous):
It was part of my Differential equation hw..I was stuck on the integration
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OpenStudy (anonymous):
what year are you?
OpenStudy (anonymous):
Junior but haven't taken calc in over 5 years!
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
man too many questions on this forum
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OpenStudy (anonymous):
right
OpenStudy (anonymous):
You? Math major
OpenStudy (anonymous):
no i am a communication engineer
OpenStudy (anonymous):
Cool well best of luck and thanks again :)
OpenStudy (anonymous):
you too all the best i will see who can i help here