SOMEONE HELP (Picture Below)
There is no n in the expression... Sure that it is the question is right?
Yes this is the right question
i think further info is needed
is this the whole question ?
What the picture says is my question, Thats why i need help. Yes it's the whole question.
hmm its a little out of my range. so i might get it wrong. ill leave it up to @SmartWish
good luck
@phi can you help me please
The question is incomplete, it should be an n in the expression as far as i know
But there isnt . Whats posted is the question. I dont understand.
I think the x is a typo, and they mean n do you have the formula for the sum of a geometric series ?
No . i dont understand this problem at all thats why i need your help. There probably is a typo, but i have no idea. Whats on that picture above is my question.
See http://www.mathsisfun.com/algebra/sequences-sums-geometric.html scroll down to summing a geometric series
I did and there probably is a typo, but does that mean i cant get help.
@phi
the formula is \[\sum_{x=0}^{N-1}ar^x = a \left( \frac{ 1-r^N }{ 1-r } \right)\]
Okay thank you. keep explaining please.
match the formula to your problem what is "a" in your problem
alrighty thank you
in sigma there is N and in equation there is x?!!
can you help me with this problem to @phi
can you identify what is "a" ? and what is r ?
for which one ?
your first problem (the one with the typo)
ok hold on
I still dont get it
your second problem is : it converges it has a sum (C)
okay @Roh so what do i do to get my answer?
look the denominator is decreasing so it converges to 0 you can just prove it and cannot get the exact number
okay and whats next
\[\sum_{n=1}^{\infty} \frac{ 1 }{ 5n }\] this is how ur problem can be expressed
wait are we talkinmg about the same problem.
oh my god, we are discussing about the second problem of yours and i expressed your second problem in a sigma form ,so you can prove that the denominator is increasing so it converges to 0
@SmokeysTheName
@Roh it converges; it has a sum is that the right answer?
@SmokeysTheName according to me yes it is the right answer
okk
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