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use integration by parts to find integral of (ln(4x))^2
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\[\int\limits_{}^{}(\ln(4x))^2\] dx
I'm not sure what to make u and what to make dv...
you are familiar with the formula for using integration by parts, correct?
yes
\[uv-\int\limits_{}^{}v (du)\]
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\[\int\limits_{}^{}fdg = fg - \int\limits_{}^{}gdf\] i would start with this f = ln^2|4x| df = (2ln|4x|)dx dg = dx g = x Can you proceed from here?
same formula, i just used the notation im familiar with
okay, Yeah I think so. Thanks for the help!
wait df should be 2ln|4x|) / (x) dx
np
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