find the real or imaginary solutions by factoring?
x^3 + 4x^2 + 2x = -8

Question

find the real or imaginary solutions by factoring?
x^3 + 4x^2 + 2x = -8

whpalmer4 · Answer

Try factoring by grouping.$$x^3+4x^2 +2x = -8$$$$x^3+4x^2 + 2x + 8 = 0$$$$(x^3 + 4x^2) + (2x + 8) = 0$$Can you pull out any common factors from the parentheses?  After doing so, do you have any ideas on how to proceed?

anonymous · Answer

2 and 1

anonymous · Answer

do i split the equation in half and have one positive and one negative solution?

whpalmer4 · Answer

Show me what you get after you factor those expressions...

anonymous · Answer

(x^3 + 2x^3) = (2x +4)?

whpalmer4 · Answer

No, I want you to factor $x^3 + 4x^2$

anonymous · Answer

x^5 + 4

whpalmer4 · Answer

No, factor it!  

What is $$x^2(x+4)$$when multiplied out?

anonymous · Answer

x + x( x + 4)

whpalmer4 · Answer

No, how do you come up with that?

$$x^2(x+4) = x^2*x + x^2*4 = x^3 + 4x^2$$
Does that look familiar? :-)

whpalmer4 · Answer

@Relientkluver