Question

find the real or imaginary solutions by factoring?
x^3 + 4x^2 + 2x = -8

Answer 1

Try factoring by grouping.\[x^3+4x^2 +2x = -8\]\[x^3+4x^2 + 2x + 8 = 0\]\[(x^3 + 4x^2) + (2x + 8) = 0\]Can you pull out any common factors from the parentheses? After doing so, do you have any ideas on how to proceed?

Answer 2

2 and 1

Answer 3

do i split the equation in half and have one positive and one negative solution?

Answer 4

Show me what you get after you factor those expressions...

Answer 5

(x^3 + 2x^3) = (2x +4)?

Answer 6

No, I want you to factor \(x^3 + 4x^2\)

Answer 7

x^5 + 4

Answer 8

No, factor it!

What is \[x^2(x+4)\]when multiplied out?

Answer 9

x + x( x + 4)

Answer 10

No, how do you come up with that?

\[x^2(x+4) = x^2*x + x^2*4 = x^3 + 4x^2\]
Does that look familiar? :-)

Answer 11

@Relientkluver