Question

Evaluate the integral from 5e to 1 of 1/x dx

Answer 1

\[\int \frac{1}{x}dx =ln(x) + C\]
Just sub in the limits.

Answer 2

I mean 1 to 5e

Answer 3

Well, have you atleast tried it?

Answer 4

but what's 5e

Answer 5

Just sub it in..assuming \(e=2.71...\) fyi; \(e\) is not a variable.

Answer 6

1+1n5?

Answer 7

\(ln(1) +ln(5e)

Answer 8

either one?

Answer 9

both

Answer 10

how do you keep your latex code on the same line as regular text?

Answer 11

\[\(\)\]@kirbykirby

Answer 12

ahh coolies :) thanks hehe

Answer 13

:)

Answer 14

For the integral though, you can "pretend" you are integrating from 1 to 5, and you'll get \( ln(5) - ln(1)\) and substitute the "5" with "5e": \( ln(5e)-ln(1)\)
but ln(1) = 0 and ln(5e) = ln(5)+ln(e) by log rules and ln(e) = 1

So the final answer is " \( 1+ln(5)\)"

Answer 15

\(e\) is just a number like \(\pi\), you just keep it written that way