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Mathematics 14 Online
OpenStudy (anonymous):

What is the equation of the following line?

OpenStudy (anonymous):

OpenStudy (blurbendy):

Same thing as last time! Try it.

OpenStudy (anonymous):

how do you replace a #? @blurbendy

OpenStudy (blurbendy):

in an ordered pair such as (2, -8) two would be the x-value and -8 would be the y-valie

OpenStudy (anonymous):

so is it b?

OpenStudy (anonymous):

cause that is true :)

OpenStudy (blurbendy):

no, we need to involve 2 somehow

hartnn (hartnn):

no... you can use the alternate way i mentioned..should i mention again ?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

how do we? @blurbendy

OpenStudy (blurbendy):

it has to be a function that has 'x' in it

hartnn (hartnn):

you can use the equation of line through origin as y=mx since (2,-8) lies on line , plug in x=2, y=-8 to get 'm'.

OpenStudy (blurbendy):

he's basically saying what i'm saying. a line can be represented by y = mx y will be the result of m*x. So, if you put 2 in for x, which constant value (or slope) will give you -8?

OpenStudy (anonymous):

so then do you divide them?

OpenStudy (blurbendy):

yes, -8 / 2 = ???

OpenStudy (blurbendy):

yup! so which function is it?

OpenStudy (blurbendy):

good job!

hartnn (hartnn):

\(\checkmark \)

OpenStudy (anonymous):

Okay awesome! So in these problems, you just divide those #s? :)

hartnn (hartnn):

only if the line is passing though origin 0,0

hartnn (hartnn):

if the line is not passing through origin, and 2 points are given, then use the 2-point form : \((y-y_1)=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)\)

OpenStudy (anonymous):

Okay! thank u SO much! I have another one like this imma post i think i know it but i wanna make sure :)

OpenStudy (raden_zaikaria):

anwer is c

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