Question

PLEASE HELP
on jan 1, 2010, Chessville has a population of 50,000 people. Chessville then enters a period of population growth. Its population increases 7% each year. On the same day, Checkersville has a population of 70,000 people. Checkersville starts to experience a population decline. its population decrease 4% each year. During what year will the population Chessville first exceed that of Checkersville? Show work and explain steps.

Answer 1

What have you worked so far?

Answer 2

50,000 * .07x= ?

Answer 3

and 70000 * .04x= ?

Answer 4

Do you have a textbook? Look up expontential growth and decay, or half life in your index and find the page.

Answer 5

no i dont have a text book with me. staying at my dads. forgot it. all i remember about is that you take them and sorta make em into 1 equation

Answer 6

50,000(1.07)^t =
70,000(1-.04)^t =
70,000(.96)^t
(1.07/.96)^t=
(70,000/50,000)=1.4
t ln (1.07/.96)
= ln(1.4)
.10848 t = .33647

t=3.102

So population will be equal in 3.102 years

Answer 7

thanks

Answer 8

ur welcome

Answer 9

WOah when did mik get smart lolol jk

Answer 10

shhhh im not smart but ik this one lmfao

Answer 11

Do I write it exactly like u did or just put the answer?

Answer 12

I have this same question

Answer 13

@mikala1 can you explain how you did it?