|(10y+30)/(3)|<10
solve the absolute value inequality
multiply by 3 on both sides
then subtract 30 on both sides
then divide both sides by 10 :)
can you do it now ?
so it would be 10<10y+30<10?
\[-10 < \frac{10y + 30}{3} < 10\]
the answer i get is y<0 but i need to figure out how to get -6 on the other side. I know this answer i need to figure out how to solve
use my steps above
what did you get when you did first step ?
@AravindG,no disrespect but your steps are incorrect
-30<10y+10<30 then divide by 10 i get -3<y<3
oh sorry !!! I didnt see the modulus sign !! thanks for spot @Hero
-6<y? by minusing the 3 from the right side?
-6<y<0
\[-10 < \frac{10y + 30}{3} < 10\] Multiply all sides by 3: \[-30 < 10y + 30 < 30\] Subtract 30 from all sides: -60 < 10y < 0 Divide all sides by 10: -6 < y < 0
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