f(x) = 3x + 2; g(x) = 3x - 5 find f/g
please help
\[\frac{f(x)}{g(x)} = \frac{3x + 2}{3x - 5} = \frac{3x -5 + 7}{3x -5} = \frac{3x - 5}{3x - 5} + \frac{7}{3x - 5} = 1 + \frac{7}{3x - 5}\]
Hi Hero
Hi @Marlins0412
so the answer to this problem is 1-7/3x-5?
Now just think about it for a minute and realize for yourself what the correct answer is.
Also realize that no one even bothered to dispute my result
Ok but what would be the domain though?
Any x as long as x ≠ 5/3
can you help with 1 more please ?
Okay
f(x) = 4x + 7, g(x) = 3x^2 Find(fg)(x)
\[(fg)(x) = f(x) \dot\ g(x) = (4x + 7)\dot\ (3x^2) = 4x(3x^2) + 7(3x^2) = 12x^3 + 21x^2\]
Thanks so much if you don't mind i have a few more but its totally up to you!
I'm more interested in understanding whether or not you're getting this.
As you do these instructions i am completely understanding your so good! May you help with more?
I guess, but like I said, I'm more interested in what you can do after I've shown you.
I understand what directions you give. THe next problem is Find f(x) and g(x) so the function can be expressed as y = f(g(x)). y=(7/x^2)+10
f(x) = x + 10 g(x) = 7/x^2 f(g(x)) = f(7/x^2) = (7/x^2) + 10
ok so you did the square of each one i see what you did. Wow your a teacher i bet!!
THe next one i need help with is f(x) = 3x + 9, g(x) = 5x^2 Find (f+g)(x)
How do you know I'm not a HS Student? When I was in high school, I did these exactly the same.
wow you must be a brilliant person!
Add you have to do is add f(x) + g(x) = (3x + 9) + (5x^2)
Add them and let me know what you get.
well im thinking the answer is 15x^3+45x
5x^2 + 3x + 9 is what i got when adding...
Yes, correct. You can only combine like terms. Since there are no like terms to combine, you simply express the addition as a quadratic expression.
So the answer is 5x^2 + 3x + 9 (not 15x^3 + 45x)
right so the first answer i got was multiplying//
do you know how to do inverses?
"Do I know how to do inverses?"...You're funny
The question is, "Do you know how to do them?".
Find the inverse of the function. f(x)=x^3-3
Im saying for you to help me out with them...
`1.` Replace f(x) with y `2.` Add three to both sides `3.` Cube root both sides `4.` Swap x and y `5.` Replace y with \(f^{-1}{(x)}\)
x+2/7?
are you still there?
If that's what you got, you didn't follow my steps exactly.
is it x-2/7 ?
Of course it isn't
i know its f^_1x but after that is where i need the help
Bro, just follow the steps I gave you.
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