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Calculus1 15 Online
OpenStudy (anonymous):

How do you derive this formula?

OpenStudy (anonymous):

OpenStudy (anonymous):

You use the chain rule: So sqrt, is the same as whole to the (1/2) power.

OpenStudy (anonymous):

GO from there: Like so: \[v_i = \sqrt{\frac{ gR^2 }{ 2H }}= ({\frac{ gR^2 }{ 2H }})^{\frac{ 1 }{ 2 }}\]

OpenStudy (anonymous):

so it would look like (gR^2/2H)^1/2

OpenStudy (anonymous):

Yup, and go from there.

OpenStudy (anonymous):

hold on give me a sec please

OpenStudy (anonymous):

No rush.

OpenStudy (anonymous):

is it (gR^2/ sqrt 2H)

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