Question

What is the simplified different quotient of f(x)=x^2+4x-3?

Answer 1

2x+4

Answer 2

My book has the answer as 2x+h+4, was wondering if you could please go step by step with me you obviously know the correct steps just left out something, thanks

Answer 3

simplified different quotient of f(x) is,
=[f(x+h)-f(x)]/h
here f(x)=x^2+4x-3
so,
s.d.q=[{(x+h)^2+4(x+h)-3}-{x^2+4x-3}]/h
=[x^2+2xh+h^2+4x+4h-3-x^2-4x+3]/h
=[2xh+h^2+4h]/h
=2x+h+4