*** Will give you a medal ***
Compare the graphs of the inverse variations by comparing asymptotes, similar points, lines of reflections, and quadrants.
y=-0.7/x and y=-0.9/x
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OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
are you able to graph these two equations
OpenStudy (anonymous):
yeahh
jimthompson5910 (jim_thompson5910):
what similarities do you see
OpenStudy (anonymous):
they are both negatives and decimals
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jimthompson5910 (jim_thompson5910):
good, so they are reflected versions (over the x-axis) of y = 1/x
OpenStudy (anonymous):
yes.
jimthompson5910 (jim_thompson5910):
they are also compressed a bit compared to y = 1/x, although, y = -0.7/x is a bit more compressed than y = -0.9/x
jimthompson5910 (jim_thompson5910):
which quadrants do both go through?
OpenStudy (anonymous):
3 and 4 ?
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jimthompson5910 (jim_thompson5910):
close, but it's 2 and 4
jimthompson5910 (jim_thompson5910):
and finally, what are the asymptotes of each
OpenStudy (anonymous):
i have no idea.. idk how to do those.
jimthompson5910 (jim_thompson5910):
what's the vertical asymptote of y = 1/x
OpenStudy (anonymous):
idk. idk how to do that.
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jimthompson5910 (jim_thompson5910):
notice how if x = 0, then you get an undefined error
jimthompson5910 (jim_thompson5910):
because you can't divide by zero
jimthompson5910 (jim_thompson5910):
so the vertical asymptote is x = 0
OpenStudy (anonymous):
yeah
jimthompson5910 (jim_thompson5910):
the vertical asymptotes of y=-0.7/x and y=-0.9/x are both x = 0 because of that same reason
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jimthompson5910 (jim_thompson5910):
similarly, the horizontal asymptotes are y = 0
a graph will help see this and you can find the domain of the inverse to get the same thing