Question

Two planets of rdii in the ratio of 2:3 are made from the materials of density in the ratio 3:2.
Then the ratio of their accelerations due to gravity g1/g2 at the surface of the two planets will be

Answer 1

@shubhamsrg

Answer 2

r is inversly propertional to d
so r2/r1 = d1/d2

Answer 3

\[\frac{r_{1}}{r_{2}}=\frac{2}{3}\]\[\frac{d_{1}}{d_{2}}=\frac{3}{2}\]\[Find\ \frac{g_{1}}{g_{2}}\]

Answer 4

g1/g2=3/2*2/3 =1

Answer 5

i m not sure

Answer 6

\[g=\frac{Gm}{r^2},\ G=6.67^110^{-11}\]

Answer 7

\[d=\frac{m}{V}\]\[m=d*V\]

Answer 8

u have confuse me

Answer 9

acceleration due to gravity is determined by the g(m,r) equation. G is some gravitational constant. What class is this for? Physics?

Answer 10

g = GM/r^2

M = VD
V= 4/3 pi r^3

SO, does it help ?

Answer 11

this is the question of class X

Answer 12

but here are r1 and r2

Answer 13

r1 is the radius of the first planet, r2 is the radius of the second planet. d1 is the density of the first planet, d2 is the density of the second planet.