Question

The moment of inertia of a thin sheet of mass m and radius R about AB ?

Answer 1

Use the parallel axis theorem

Answer 2

I (AB) = I (CM) + m * perpendicular Distance

Answer 3

Ryt

Answer 4

in other words, start with the moment of inertia of the disc rotated through an axis running through the center of the disc, then apply the theorem to shift the rotation axis.

Answer 5

Yes

Answer 6

so mR^2 /4 + m R^2

Answer 7

@JamesJ ??

Answer 8

No, the moment of inertia rotating a disc about its center axis is mR^2/16

Answer 9

So..wat is ur answer

Answer 10

17mR^2 / 16

Answer 11

@JamesJ

Answer 12

Whats the perpendicular distance between the CM and the axis in this problem?

Answer 13

R

Answer 14

No, the *perpendicular* distance