Question

Algebra 2 please help!!!!

Answer 1

n^4-11n^2+30/n^4-7n^2+10
simplify

Answer 2

you have to factor the top and bottom to see what like factors can cancel out

Answer 3

i think i got the answer hold on just a minute if u dont ,mind

Answer 4

i don't know how to factor it....
and ok :)

Answer 5

is it becasue of the ^4 and ^2? or just becasue you dont know how to factor?

Answer 6

yeah cuz of the ^4 and ^2

Answer 7

its just a disquised quadratic: n^4 = (n^2)^2 so we can rewrite this cleaner by letting x = n^2

Answer 8

n^4-11n^2+30
--------------
n^4-7n^2+10


(n^2)^2-11n^2+30
-----------------
(n^2)^2-7n^2+10


x^2-11x+30
------------
x^2-7x+10

Answer 9

now you should be able to recognize it as a more normal quadratic looking setup

Answer 10

yeah so would it be.... (x -5)(x-6)/(x-2)(x-5)

Answer 11

correct, and the x-5 parts can cancel

Answer 12

so x-6/x-2...? are there any restirctions?

Answer 13

oh wait those should be n^2 iinstead of x right?

Answer 14

x not equal 2 fer sure; but you should prolly want to include the original restriction with x=5 as out.

recall that we said let n^2 = x
therefore; x = sqrt(n)

and we can continue the simplifications with that\[\frac{\sqrt n-6}{\sqrt n-2}\]

Answer 15

depending on the textbook you have to work from, i believe that most simplifications in general hate sqrts in the bottom, so we would have to run a conjugate on it

Answer 16

they just want it like n^2-6/n^2-2 where n does not equal 5 or 2... :) thanks for all your help!!

Answer 17

if there are any options to guide us towards, that would be nice :)

Answer 18

cool

Answer 19

n not equal to +-sqrt(2) or +-sqrt(5) would be better restrictions :)

Answer 20

lol, i see my mismath in that n=x^2; x = sqrt n post ... good eye