Mathematics
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OpenStudy (anonymous):
Form a polynomial function with a degree of 4, zeros 2-4i; 4 multiplicity 2. Please help!
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OpenStudy (anonymous):
i will show u the steps then u conclude
OpenStudy (anonymous):
Perfect!!! Thank you very much!!!!!!!
OpenStudy (anonymous):
step one: you can get a zero from multiplying the complex number by its conjugant
OpenStudy (anonymous):
so in your case we have:
OpenStudy (anonymous):
\[(2-4i), (2+4i)\]
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OpenStudy (anonymous):
sorry am on the phone i will continue the whole problem after am done
OpenStudy (anonymous):
No problem! I had (x-(2-4i)(x-(2+i)(x+4)^2
OpenStudy (anonymous):
yes that is correct apart from a missing 4 in ur cojugent
OpenStudy (anonymous):
so u are having a problem multiplying them
OpenStudy (anonymous):
I get to this point and I'm c lost! I don't know what to do next!
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OpenStudy (anonymous):
well u have to multiply the whole thing to get the polynomial
OpenStudy (anonymous):
the best way to do that is to simplify the product let me show u
OpenStudy (anonymous):
i am writing a simple method for u to always be able to solve such a problem quickly
OpenStudy (anonymous):
\[(x+iy)(x-iy)=x^2-(iy)^2\]
OpenStudy (anonymous):
r u there?
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OpenStudy (anonymous):
I'm here sorry :-)
OpenStudy (anonymous):
\[[x-(2-4i)][x-2+(2-4i)][(x+4)^2]\]
OpenStudy (anonymous):
now let's solve the complex values first
OpenStudy (anonymous):
\[=[(x-2)+4i)][(x-2)-4i)]\]
OpenStudy (anonymous):
can u see i rearranged it in terms of real and imaginary parts ok
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OpenStudy (anonymous):
\[=(x-2)^2-(4i)^2\]
OpenStudy (anonymous):
Yes I follow that
OpenStudy (anonymous):
\[=x^2-4x+4+16=x^2-4x+20\]
OpenStudy (anonymous):
Oh yeah that formula you gave earlier makes sense now
OpenStudy (anonymous):
\[=[x^2-4x+20][(x+4)^2]\]
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OpenStudy (anonymous):
now lets expand
OpenStudy (anonymous):
so u can see we are getting a 4th order polynomial
OpenStudy (anonymous):
\[=[x^2-4x+20][x^2+8x+16]\]
OpenStudy (anonymous):
the final answer hence is:
OpenStudy (anonymous):
\[=x^4+4x^3+4x^2+96x+320\]
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OpenStudy (anonymous):
i did that on piece of paper
OpenStudy (anonymous):
I was still calculating mine, but I got the same answer!
OpenStudy (anonymous):
Thank you so very much for taking the time to actually walk me through step by step!!!!!!!
OpenStudy (anonymous):
good all the best
OpenStudy (anonymous):
don't forget my medal hehehe
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OpenStudy (anonymous):
How do I do it
OpenStudy (anonymous):
how do i know hehehe, i really don't know
OpenStudy (anonymous):
i am just kidding anyways
OpenStudy (anonymous):
Figured it out :-) there you go, you have a medal !!! Thanks again!!!!!