Find all solutions in the interval [0, 2π).
cos x = sin x
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OpenStudy (anonymous):
there are several ways to solve this problem
OpenStudy (anonymous):
@mathsminds would factoring work for this problem?
OpenStudy (anonymous):
\[\cos x = \sin x\]
OpenStudy (anonymous):
divide both sides by cos x
OpenStudy (anonymous):
\[\frac{ cosx }{ cosx }= \frac{ sinx }{ cosx }\]
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OpenStudy (anonymous):
\[tanx=1\]
OpenStudy (anonymous):
\[x = \arctan(1)\]
OpenStudy (anonymous):
\[x=\frac{ \pi }{ 4 }\]
OpenStudy (anonymous):
@mathsmind and x = 5pi/4
OpenStudy (anonymous):
i want to show u how to get all the solutions between [0.2pi]
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OpenStudy (anonymous):
if u know how to do that then all the best
OpenStudy (anonymous):
do u want to see another method of how to solve this question or not?
OpenStudy (anonymous):
ur solving for tan as being +ve
OpenStudy (anonymous):
@mathsmind no, thank you! those were the two solutions and I figured it out through your first method :)
OpenStudy (anonymous):
and u know that tan will be +ve in the first quarter and the third quarter is +ve
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OpenStudy (anonymous):
but by the way u can't use that first method always, this is just a special case which u can do so, however u should get to the habit of using trig identities