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Mathematics 8 Online
OpenStudy (anonymous):

what is the slope of the line below? If necessary, enter enter your answer as a fraction in lowest terms

OpenStudy (anonymous):

OpenStudy (anonymous):

@amistre64 @JamesJ

OpenStudy (anonymous):

1/3

Directrix (directrix):

@Will679 --> I did not get that. Please post your work. Thanks.

OpenStudy (anonymous):

I got 6-3/ 12-6 ? :)

Directrix (directrix):

@Will679 From the OpenStudy Code of Conduct: OpenStudy values the Learning process - not the ‘Give you an answer’ process •Don’t post only answers - guide the asker to a solution.

OpenStudy (anonymous):

It's okay :) Thanks I got it already :)

OpenStudy (anonymous):

ok so what i did was just looked at eh picture and counted how many times you need to move ot the right form the negative x position and then i counted up from there and got 2/6 and then reduced that.... getting 1/3 hope taht wasnt' confusing it is kinda hard to type out how i did it...

Directrix (directrix):

The slope of a line is a constant rate of change. Change as in the change in y over the change in x. (-6,3) and (12,6) slope = [ (6 - 3)]/[12 - (-6)] Slope = ? ------------ @pleasehelpmeonmath --> Sign error here, I think: I got 6-3/ 12-6 ? :) @Will679 Your intrepretation is at the core of understanding slope. It should produce a correct answer. I got 3/18 which is 1/6. Should it be 1/3?

OpenStudy (anonymous):

haha actually just realized i counted wrong it shoudl be 1/6 :P haha thansk for correcting me :P

Directrix (directrix):

@Will679 --> I counted over 18 and then up 3 which would be 3/18. Leaving the answer at 3/18 in a slope problem makes more sense to me because the units over and units up are accurate.

OpenStudy (anonymous):

Yeah i just counted over 6 and up one cuz it runs into the line then and you don't have to reduce then... @Directrix

OpenStudy (anonymous):

not that reducing is hard in this circumstance.. :P

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