Question

find the derivative of y with respect to x, t or theta as appropriate.
y= ln(cos(ln theta))

Answer 1

its very simple

Answer 2

please help me

Answer 3

-(1/cos(ln theta))*(sin(ln theta)*1/theta

Answer 4

\[\frac{d(ln(cos(ln(\theta)))}{dx}\]

Answer 5

Should be dTheta

Answer 6

the answer is - (tan (ln theta))/ theta

Answer 7

i just dont no how to get to that

Answer 8

\[\frac{1}{cos(ln(\theta))}*-sin(ln(\theta))*\frac{1}{\theta}\]\[\frac{-sin(ln(\theta))}{cos(ln(\theta))}\frac{1}{\theta}\]\[=\frac{-tan(ln(\theta))}{\theta}\]Let me know if we need to go over anything.

Answer 9

thank you this explains it :)

Answer 10

Ok good luck in calculus

Answer 11

thank you its really hard. just trying to keep up. have a test coming up i just hope to pass it. thank you for ur help!

Answer 12

Sure thing. Private message me if you ever want to discuss more problems.

Answer 13

ok thank you!