Find the amount of time required for an amount to double at the given rate if the interest is compounded continuously. Problem---> 5%
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OpenStudy (tkhunny):
\(e^{0.05\cdot t} = 2\) - Solve for t.
OpenStudy (anonymous):
can you explain ? @tkhunny
OpenStudy (tkhunny):
I already did. Have you used logarithms? That's all you need.
OpenStudy (anonymous):
yes , but how would i solve for t?
OpenStudy (anonymous):
@zaynahf
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OpenStudy (tkhunny):
Seriously, use logarithms.
OpenStudy (tkhunny):
Base 'e' logarithms? Natural logs? Let's see what you get.
OpenStudy (anonymous):
plug in e^0.05 into my calculator ?
OpenStudy (anonymous):
@zaynahf
OpenStudy (tkhunny):
You did say that you had used logarithms. It appears this is not the case.
If: \(e^{0.05t} = 2\)
Then: \(\ln\left(e^{0.05t}\right) = \ln(2)\)
Further: \(0.05\cdot t\cdot\ln(e) = \ln(2)\)
Finally: \(0.05\cdot t = \ln(2)\)
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OpenStudy (anonymous):
Then divide both sides by 0.05 ?
OpenStudy (anonymous):
=13.863?
OpenStudy (tkhunny):
That's it. good work.
Let's try another one so I can see you deal with the logarithms.