Question

A student bought a box of crayons and 5 reams of paper for $54. She bought 5 boxes of crayons and 3 reams of paper for $50. What is the cost of each box of crayons and each ream of paper?

Answer 1

Well, you have to set up a system of equations, so first set your variables:

C = crayons, P = Paper.

then set up equations for the sentence: A student bought a box of crayons and 5 reams of paper for $54.

So the equation is C + 5P = 54

And the second one for: She bought 5 boxes of crayons and 3 reams of paper for $50.

5C + 3P = 50.

Now, using these two equations, solve the system by elimination or substitution.

Answer 2

I tried but when I tried solving for P, I got like 10.909090909090.

Answer 3

Hmm, well let's go through it shall we?

C + 5P = 54 ----> C = -5P + 54
5C + 3P = 50.

then we can do the following by subbing first into second

5(-5P + 54) + 3P = 50
And you get:

-25P + 270 + 3p = 50
Then rearrange to get:

-22P = -220
So it follows that: 22P = 220, then divide by 22 to get P = 10.

Use P = 10 (which is cost of paper) in the first equation to get C (cost of crayons).

Answer 4

THANK YOU SO MUCH! You helped me out alot!
HAVE A WONDERFUL EVENING!

Answer 5

You too, and your welcome!

Answer 6

I like that you don't just give peopl the answer!

Answer 7

*people

Answer 8

Oh yea, don't worry about that. :p