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Physics 18 Online
OpenStudy (anonymous):

You are on an airplane traveling 30° south of due west at 110.0 m/s with respect to the air. The air is moving with a speed 39.0 m/s with respect to the ground due north.

OpenStudy (agent0smith):

Okay... Is there a question?

OpenStudy (anonymous):

Oh sorry here it is. 1) What is the speed of the plane with respect to the ground. 2)What is the heading of the plane with respect to the ground? (Let 0° represent due north, 90° represents due easth) Also if you dont mind i need way how you solve it because I have got an idea how to work with this kind of tasks.

OpenStudy (anonymous):

call the velcocity of the plane wrt the air VPA, and the velcocity of the air wrt the ground VAG … velocities are vectors, so they obey the laws of vector addition … you want VPG, which is VPA + VAG … there are two ways to do this … i] draw a vector triangle of the three velocities, with vertices labelled P A and G, and with arrows along each side pointing the correct way, and use the sine and cosine rules ii] use x and y components (separately)

OpenStudy (agent0smith):

I think this is what it looks like |dw:1360214693319:dw|

OpenStudy (anonymous):

it make sense tnx. i got write answer by coslaw. but what about second question?

OpenStudy (agent0smith):

I think you just need to find the angle for the heading. Should be able to use the sine rule. |dw:1360217678537:dw|

OpenStudy (agent0smith):

\[\frac{ \sin 60 }{x } = \frac{ \sin y }{ 39 }\] x is what you found for speed, in part a. |dw:1360217730638:dw|

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