Question

Ethylene glycol (antifreeze) has a density of 1.11 g/cm^3.

1/What is the mass in grams of 385mL of this liquid?

2/What is the volume in liters of 3.43 kg of this liquid?

Please it is due in one hour!

Answer 1

M = D*V
cm^3=mL
so
(1.11 g/cm^3)* 385 mL
^
but we cant have cm^3 so we replace it by cm^3=mL

(1.11 g/(mL))* 385 mL =427.35 g

Answer 2

2 What is the volume in liters of 3.43 kg of this liquid?
density of 1.11 g/cm^3.
M/D=V
Plug in info
(3.43 kg) / (1.11 g/cm^3)=V
^ not right units, suppose to be in g so move over 3 to right and you get it in g
(3430 g) / (1.11 g/cm^3)=3090.090090*cm^3

put you want it in litters

3090.090090*cm^3
^ replace by mL
3090.090090 mL
^ replace by 1 L= 1000 mL -> 1/1000 L=mL

3.090090090 move decimal 3 places to left

Answer 3

so the final answer for the second part is 3.090090090?

Answer 4

rougly 3 liters

depends on sigfigs

3.09 L

Answer 5

Thanks :)

Answer 6

de nada