Question

Easy question for most people :P
WIll give medal and fan :)
An object is brought to rest from a velocity of 24m/s due north in 16 seconds. Find (a) the displacement , (b) acceleration and distance travelled

Answer 1

for i think you use this formula am i correct?
s= ut + 1/2at^2

Answer 2

since you know the starting velocity and end velocity as well as the time spent,
you can use the following equations
$$S=\frac{(u+v)}{2}t$$ and for acceleration,
$$v=u+at$$

Answer 3

i just started physics and i dont know this formula yet :P
S=(u+v) /2 * t

Answer 4

our teacher gave us 3 formulas to work with.
1-3 equations of motion

Answer 5

yes threre are three equations
\[\Large v_{f}=v_{i}+at\]
\[\Large S=v_{i}t+1/2at^2\]
\[\Large 2as=v_{f}^2-v_{i}^2\]
where
vf=final velocity
vi=initil veloct
s=distance covered
a=acceleration
t=time

Answer 6

using the first equation
since objecvt is brought to rest so
vf=0
vi=24m/sec
t=16
we can find a using first equation
\[\Large 0=24+16a\]
\[\Large a=-24/16=-1.5m/\sec^2\]
use the other equation to get distance .

Answer 7

we use which equation? number 2?

Answer 8

im pretty sure thats not right... The object cannot be deccelerating???

Answer 9

If it is not deccelerating how can a moving object be brought to rest?

Answer 10

oh yes :P

Answer 11

so im going to use which formula to work out displacement?
2nd or 3rd
I think 2nd

Answer 12

the object is decelarating because you have brought it to rest . think of if you are driving a car and you apply brakes what will happen ???? acceleration or deceleration ??

Answer 13

deceleration yea i understand that now