Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

If ABC~STO, what is the length of BC? ( Picture attached below )

OpenStudy (anonymous):

OpenStudy (anonymous):

similar triangles means they have proportional sides... solve the proportion according to "between the triangles" correspondence: \(\large \frac{33}{18}=\frac{x}{21} \)

OpenStudy (anonymous):

So would I multiply 33 by 21 to get 693 and 18 by x 18x then what? Sorry if this is wrong I'm bad at this and a little confused lol

OpenStudy (anonymous):

@agent0smith Can you help me with this?

OpenStudy (anonymous):

@agent0smith Any chance you know this?

OpenStudy (anonymous):

@Chelsea04 Can you help?

OpenStudy (anonymous):

so these triangles as proportionate, that means that there are corresponding sides

OpenStudy (anonymous):

so, 33 is the larger (one) of 18.

OpenStudy (anonymous):

and BC is the larger one of 12.

OpenStudy (anonymous):

so using ratios 33/18=BC/12

OpenStudy (anonymous):

\[33/18=BC/12\] so cross multiply BC x 18 = 33 x 12

OpenStudy (anonymous):

33x12= 693 BCx18 = ?

OpenStudy (anonymous):

if BC x 18 = 33 x 12 then BC x 18 = 693 then BC = 693/18

OpenStudy (anonymous):

That comes up to 38.5 does that sound right?

OpenStudy (anonymous):

yea, sounds right

OpenStudy (anonymous):

I don't think that's it lol but I don't know

OpenStudy (anonymous):

just wait...

OpenStudy (anonymous):

used a calculator and got 22

OpenStudy (anonymous):

found it! 33 x 12 = 396, not 693

OpenStudy (anonymous):

Oh wow I must of typed it in wrong lol yea its 22 lol

OpenStudy (anonymous):

happy with that answer?

OpenStudy (anonymous):

Thanks for the help much appreciated!

OpenStudy (anonymous):

no problem :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!