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Find the indefinite integral of (y+(2/sin^2y))dy
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Hint: what's the derivative with respect to y of cot(y) ?
cscx?
No. But it is related to the 1/sin^2 y in your question
I still don't get it?
csc^2x
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\[ \frac{d }{dy} \cot y = - \frac{1}{\sin^2 y} = - \csc^2 y \]
Hence \[ \int \left( y + \frac{2}{\sin^2 y} \right) \ dy = \int y \ dy + 2 \int \csc^2 y \ dy = ... \]
So what's the answer?
You tell me. I've done the first few steps for you. You only have 2 more to do: evaluate each of those integrals above
y^2/2+2cotx+c
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Double check your signs!
Negative cotx
yes
Yes, thank you!!!
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