The range of the relation below is: x y -3 8 3 6 5 4 8 4 A. {−3, 2, 5, 8} B. {4, 6, 8} C. {8, 6, 4, 4} D. No range exists.
{8, 6, 4, 4} all y values
B. The range by definition is a set that contains all the y values ASSUMING that the mapping is form x to y which is to say, you represent your ordered pairs as (x,y) and not (y,x). Having that said, in a set, any two values which are equal count only as one. Here, four is repeated therefore, four counts only ONCE. B is your solution. I guarantee it.
Well then how come they would say that its C?
Because their definitions are insufficient. It is true that the range is a set of all the values of y, but the range discounts repeated numbers. While it is also true @rizwan_uet that 4 corresponds to two different values of x, it is STILL repeated. More specifically, your relation is a function and since TWO x values are mapped into ONE y value, this function is "surjective" or "onto." College set theory does not lie.
guys, there is a range. you shuld just limit the domain. so more info is needed
@khoala4pham ya u r right, i just selected C while looking at the output values. correct option is B. {4, 6, 8}
for the following function |dw:1360270996165:dw| the range is {0,1,2,....} and not {0,1,1,2,2,3,3,4,4,5,5,6,6,......} what u say @Luis_Rivera ???
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