Find the distance between the pair of parallel lines, y = x-11 & y = x-7. Select one: a. square root of 8, or appx 2.8 b. square root of 11, or appx 3.3 c. 4 d. square root of 7, or appx 2.6
The computation is slightly tedious but I will try to give you the general method. The distance between two parallel lines is found by the distance of two points on each line, connected by a line orthogonal (perpendicular) to each of these lines. In general, the slope of the orthogonal line is the negative reciprocal of the slopes: in this case, the slope is 1, so your slope you need is -1. So let's just choose the line y = -x for simiplicity's sake. You need to find the intersection betweeen y = -x and each of the original lines. This gives you two points. The distance between these two points is the distance between the line.
i still don't get it :/
just find an intercept of one line by putting let say x=0 u will get y=some value so u located a point on one line now use formula for finding the distance between line and point
its A.. right?
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