PLEASE HELP? I dont think anyone can get this i asked and asked!!! Please try best answer?fan?asap Describe an infinite geometric series with a beginning value of 2 that converges to 10. What are the first 4 terms of the series?
See the formula for summing the geometric series http://en.wikipedia.org/wiki/Geometric_series#Formula when n= infinity and r is less than 1, r^n approaches zero the sum of an infinite number of terms becomes \[ S= \sum_{n=0}^{\infty} ar^n= \frac{a}{1-r} \]
a is the first term. they tell you that. S is the sum of an infinite number of terms. they tell you that. now use algebra to solve for r.
thats what i dont get it why is there "2 converge to 10" thats what confuses me you dont have to give me the answer but a little more hints would be greatly apprieciated
You have to know about a geometric series For example, there is this series It starts with 1/2 as the first term \[ \frac{1}{2} \] then we set the next term to 1/2 times the first term. 1/2 * 1/2 is 1/4 \[ \frac{1}{2} + \frac{1}{4}\] the 3rd term is 1/2 times the second term. 1/2 * 1/4 = 1/8 \[ \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + ...\] we do that forever
Describe an infinite geometric series with a beginning value of 2 that converges to 10 that is asking for a series whose first term is 2 2 and we multiply the 2 times a factor (which we don't know YET, but will call r) the first two terms are: \[ 2 + 2r \] the 3rd term is r times the 2nd term: r * 2r = 2r^2 \[ 2 + 2r + 2r^2 + ....\] we keep doing that forever but when we add them all up, they add up to 10 (the more terms we add the closer we get to 10, but we never *quite* get there) the series converges to 10
meaning i only plug in 2? or 2-10? im sorry i am ust confused about the question but i actually understand evrything your saying just not what the question wants me to do
luckily we have a formula for what the series converges (adds up) to: \[ 2 + 2r + 2r^2 + 2r^3 + 2r^4 + ....= \frac{2}{1-r} \] they tell us they want this thing to add up to 10 we can use the formula: \[ \frac{2}{1-r} = 10 \] I would "flip" both sides (remember 10 can be thought of as 10/1) can you do that ?
you want to solve for "r" there are a few ways to do this.
are you stuck on the algebra ?
would it be r=8?
i multiplied 1-r to 10 which led me to ------ 2= 10 * 1-r.... then i got 2=10-r. then, -8=-r then divided by -1
no, but you can check your answer this way: replace r with 8 in the equation \[\frac{2}{1-8} = ?10 \] 1-8 is -7 and 2/-7 is not 10
ill try again
oh, ok, when you multiply 1-r it is one "chunk" so put it in parens you get 2 = 10*(1-r) you have to distribute the 10. (multiply BOTH 1 and -r by 10) But I would not bother I would first, divide both sides by 10
ill tell you what i just got but it looks backwards.... r= -19
write down your steps, and I'll tell you if you are on the right track
this time i multiplied 10 by 2 nd got ... 1-r= 10*2, then, 1-r=20, subtract 1 and get .....-r=19, then divide and get r= -19
pay attention. we start at the beginning \[ \frac{2}{1-r} = 10 \] multiply both sides by (1-r) \[ \frac{2}{\cancel{1-r}} \cdot \frac{\cancel{(1-r)}}{1} = 10 \cdot (1-r)\]
now divide both sides by 10. can you do that ?
like this \[\frac{2}{10} = \cancel{\frac{10}{10}} \cdot (1-r) \]
yeah thats what i got
of course 2/10 is 1/5 \[ \frac{1}{5}= 1-r \]
so i could subtract 1 from1/5 next? to get it isolated?
yes, we could add -1 (or subtract 1, but I always think "ADD" and use negative numbers) -1+1/5 = 1-1 -r
we get -1 + 1/5 = -r it looks nicer if we multiply both sides (ALL TERMS) by -1 -1 * (-1+1/5) = -1*-r +1 -1/5 = r
4/5?
yes, 4/5 you can check 2/(1-4/5) is 2/(1/5) which is 2*5 = 10 now can you write down the first few terms? the first one is 2 2 then 2nd term is 2 * 4/5 the third term is the 2nd term times 4/5 and so on If you are ambitious, you can write down all of them, add them up and see if you get 10 (haha)
btw, try some of Khan's videos http://www.khanacademy.org/math/algebra/solving-linear-equations-and-inequalities/basic-equation-practice/v/equations-3 because solving equations is important.
@phi thank you so much your the best and i loved how you helped and explain really thank you!!
can i ask one more question? i want to see if i got it right
If you have time, start with this one http://www.khanacademy.org/math/algebra/solving-linear-equations-and-inequalities/equations_beginner/v/simple-equations and watch the next few.
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Justine earned $26,000 during the first year of her job at city hall. After each year she received a 3% raise. Find her total earnings during the first five years on the job. $138,037.53***** $1,004,704.20 $4,020.51 $108,774.30 am i right?
and i sure will!!
this is a geometric series (what a coincidence). the starting number is 26000 you multiply by 1.03 ( 0.03 is the raise 1.03 is the salary plus raise) if we write it out: 26000 + 26000*1.03 + 26000*1.03^2 + 26000*1.03^3+ 26000*1.03^4 we could just add it up, but it's better to use the formula \[ \sum_{n=0}^{4} 26000 (1.03)^n = 26000 \cdot \frac{1-(1.03)^5}{1-(1.03)}\] the bottom is 1-1.03 = -.03 the top is 1 - 1.159274 = -0.159274 the sum is \[ 26000 \cdot \frac{ -0.159274}{-0.03} = 26000*5.309135 = 138037.53
the sum is \[ 26000 \cdot \frac{ -0.159274}{-0.03} = 26000*5.309135 = 138037.53 \]
so i was right?
I got 138037.53 is that what you picked ?
yeah thats what i picked thats why i put the star and you were right thank you soooooo much:)
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