find the length of a segment with an endpoint of (2,5) and a midpoint of (5,9)
If you know an endpoint and a midpoint, you know that the length is 2x the distance between the endpoint and the midpoint, right? To find the distance between two points \((x_1,y_1),(x_2, y_2)\) use the formula \[d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\] It doesn't matter which point you decide is which.
is the answer 7
?
You tell me.
How did you arrive at that answer?
lol im asking you, am i correct?
i recheck my answer is the correct answer 5?
Show me or describe your work, and I'll tell you if you did it correctly.
okay using the distance formula that you give me
\[d = (x1 - x2) ^{2} + (y1 - y2)^{2 }\]
\[( 2- 5) ^{2 } (5-9)^{2}\]
Okay, good. So the distance from the midpoint to the endpoint is 5. What is the length of the entire segment?
\[(-3)^{2} (-4)^{2}\]
10
There you go! It's just twice the distance from the midpoint to the endpoint.
thanksssss!
Think of it as a diameter of a circle and a radius. The radius is the distance from the edge to the center, and that's what we found. The diameter is the distance from the edge through the center to the other edge, and that's what we got at the end.
true true, math really isnt my thing
In a real life situation, if I told you to put a ruler down so the center was on the midpoint, and an end was on the endpoint, I'm sure you would immediately realize that the answer was twice the distance you'd measured. But doing it on the coordinate grid with a formula, you don't have that natural instinct of how it works at first.
could you help me with my next question
I can try, before I see it, I can't know for sure :-)
find the midpoint of a segment whose endpoints are (5,8) and (-3,10)
Okay, do you know the formula for a midpoint given the two endpoints?
no
Are you ready to figure it out? :-)
yesss, you not willing to give me the answer?
Okay, let's figure it out! Suppose we have two points on a number line. One point is at x = 7, the other is at x = 3. What is the distance between them, and what is the point midway between them?
5 and im guessing midway is 2.5
Let me draw a picture:|dw:1360284303999:dw| How many points do you have to move to the right to go from 3 to 7?
4
Okay, what's half of 4? If you move that many points to the right from 3, or to left from 7, what point do you end up with?
2
Okay, so what point?
at 5
Right! What we did was take (7-3) to get the distance between them, and then we divided that in half and added it to one of the points to get the midpoint. Another way to do it would be to add the two points, and then divide by 2. That turns out to be the same thing. (7+3)/2 = 5.
im lost
i get it
sorry
Not a problem. Do you agree that we just took the average of the two points?
huh ? so in my case i would have to add 5 and 8 then divide by 2
then add -3 and 10 then divide by 2
No, not quite, you added the x and y values together, but you want to add x values to x values, and y values to y values. The midpoint is just the average of the x values, the average of the y values.
Think of it as doing each direction separately. You find the halfway point on the x-axis, and the halfway point on the y-axis, and then where the lines through those points drawn perpendicular to the axes cross is the midpoint.
okay
So what are your two x values from your points? Add them together, and divide by 2. That's the x value of the midpoint.
Similarly, take the two y values, add them together,divide by 2, and that's the y value of the midpoint.
5 and -3 right?
the answer at the end would come out to 1,9 right?
Yes!
yay, we did it
And if you think about it, if we had two points on the x-axis (both y values are 0), we get exactly the same result, because we average 0 and 0 and get 0. Similarly, if both x values are the same, we just average the y values.
Does the formula make sense to you?
thanksss, are you a teacher or something? get get it the end you saying now. but the way we slove the problem
* i dont understand the way your saying it now. but the way we slove the problem sounds easier to me
Midpoint (M) of \((x_1,y_1),(x_2,y_2)\): \[(\frac{1}{2}(x_1+x_2),\frac{1}{2}(y_1+y_2))\]
Here's a real-life application of this that I learned long ago in mechanical drawing class. Suppose you have a box, and you need to draw a line right down the middle. How can you do that? Well, you take your ruler, and you put it diagonally across the box. Move the ruler so that there are an even number of units between the spots on the ruler where it crosses the edges. Say, 2 and 8, for example. Make a mark at the halfway point on the ruler (on the box). Now go somewhere else on the box, and repeat the process. Any diagonal line works, just mark the midpoint. Now you lay down the ruler between the two points you marked, draw a straight line, and you've got your midline!
Much faster and more accurate than trying to figure out what half of 3.92543 inches is, and then measuring off that distance from one side in a couple of places.
I'm not a teacher, but I enjoy helping others learn, especially when I can see the little light bulb go on in their head as they understand something for the first time :-)
awww, you should be
could you help with the question i just posted
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