Question

\[tan^{-1}0\]
\[tan(...)=0\]
that would be \[\frac \pi 2\]
so \[tan^{-1}0=\frac \pi 2\]

Answer 1

@satellite73
Am I right?

Answer 2

i mean yes!!

Answer 3

sorry i am tired, i thought you wanted \(\tan^{-1}(1)\) you are right

Answer 4

\[tan^{-1}\sqrt 3=\frac\pi 6\]

Answer 5

now that one is wrong

Answer 6

noooooo....

Answer 7

\[\tan(\frac{\pi}{3})=\sqrt3\]

Answer 8

oh it's \[\frac \pi 3\]

Answer 9

so
\[\tan^{-1}(\sqrt3)=\frac{\pi}{3}\]

Answer 10

yeah tan is \[\frac yx\] yep makes sense haha

Answer 11

yes it is

Answer 12

awesome!