Question

Find functions f and g so that h(x) = (f ∘ g)(x).

h(x) = (6x - 14)^8

Answer 1

do u know this question has many answers

Answer 2

Oh, really? Here's the options I was given-
A. f(x) = 6x - 14, g(x) = x8

B. f(x) = 6x8 - 14, g(x) = -14

C. f(x) = x8, g(x) = 6x - 14

D. f(x) = (6x)8, g(x) = -14

Answer 3

f(x) could be f(x) =x^8, and g(x) =6x-14

Answer 4

Oh, wow, thank you so much! I appreciate it!

Answer 5

your welcome

Answer 6

for example

Answer 7

f(x) =x^4 and g(x) (6x-14)^2

Answer 8

Would that also be correct?

Answer 9

oh u have multiple choice

Answer 10

i just saw it now

Answer 11

stick to the choices u have

Answer 12

but yes if there was no multiple choice u would have a lot of answer to that question

Answer 13

for example

Answer 14

f(x) = x, and g(x)=(6x-14)^8

Answer 15

Egad, thank goodness for multiple choice questions. Thank you so much.

Answer 16

ur more than welcome, but did u know how this worked?

Answer 17

I sort of think so? If you have the time to expand it, I'd appreciate it.

Answer 18

sure

Answer 19

composite functions are very important in calculus u need really be able to visualize the inside out, especially for the sake of the chain rule

Answer 20

or another term it may be called function of a function

Answer 21

so what does f o g mean?

Answer 22

it means everything in g throw it in the bin of f

Answer 23

so let f(x) be ur container

Answer 24

Ok, so far so good...

Answer 25

so try this one f(x) = x^x^x, and g(x) = e^x^2 find g o f, and f o g

Answer 26

if you solve this problem then u can solve any composite function

Answer 27

r u there?

Answer 28

Sorry, trying to work it out.

Answer 29

ok take ur time give me a shout when u r done

Answer 30

So f o g would be...
g(x) = e^x^2
= X^x[(e^x^2)]^x

Oh, wait, I think I'm lost.

Answer 31

u need to throw e^x^2 in every x

Answer 32

Oooooh.

Answer 33

squeeze ur mind and focus this will give u a deep understanding, even if u don't get the answer

Answer 34

this is my point u need to think in depth

Answer 35

ok i will leave now u take ur time am sure u can solve, then give me the answer anytime u want ok