Find all solutions to the equation. (sin x)(cos x) = 0
anyone help me?!?!:(
Hint: if (sin x)(cos x) = 0 then sin(x) = 0 or cos(x) = 0
now use the unit circle to figure out when sin(x) = 0 or when cos(x) = 0
@jim_thompson5910 so {(pi/2)+npi|n=0,1,2.....}? |
well if n = 0, then pi/2+npi turns into pi/2 but x = 0 is a solution to sin(x) = 0
so it's close, but not quite there
does that make sense?
@jim_thompson5910 yeaaa so what would be the correct answer?
a better answer would be {n*pi/2 | n = 0, 1, 2, ...} because notice now that when n = 0, x is x = 0 when n = 1, x = pi/2 when n = 2, x = pi etc etc
pretty much, any nonnegative multiple of pi/2 is a solution
@jim_thompson5910 {(pi/2)+npi,npi|n=0,1,2 would this be right then? {(pi/2)+npi|n=0,1,2} or this?
oh i see what they did, they broke it up
so yes it would be {(pi/2)+npi,npi|n=0,1,2, ... }
one is the solution set to cos(x) = 0, the other is the solution set to sin(x) = 0
Join our real-time social learning platform and learn together with your friends!