Question

will give medal & fan! 3 more to go..

Answer 1

@Chelsea04

Answer 2

do you know the circle equation?

Answer 3

no :(

Answer 4

\[(x-h)^2+(y-k)^2=r^2\]
(h,k) is the centre
and r is the radius

Answer 5

okay! so what do I do with 14?

Answer 6

that is the radius, so if the radius is 14, that means
r=14

Answer 7

also, you need your centres to put into the equation

Answer 8

Ohhh so what are the centres? (:

Answer 9

*centre (no plural.it's a circle)
The question said that the centre (of the circle) is at the origin

Answer 10

so (h,k) refers to this centre.
h is the x-coordinate for the centre
k is the y-coordinate for the centre

Answer 11

oh alrighty! so how do you find it?

Answer 12

origin (from the question)

Answer 13

the origin is 14?(:

Answer 14

no the origin is (0,0) coordinate point

Answer 15

think of the cartesian plane:
at the centre where the two lines meet it is called the origin. we also know that here the x-co is 0 and the y-co is 0
therefore the origin is (0,0)

Answer 16

yeah

Answer 17

so...if
h=0 and k=0 and r=14,
put those values into the equation I gave you earlier and voila!

Answer 18

Oh! 14?(:

Answer 19

@Chelsea04

Answer 20

no, the equation is:
\[(x-h)^2+(y-k)^2=r^2\]
so, \[(x-0)^2+(y-0)^2=14^2\]
now simplify :)

Answer 21

but it's 0 :(

Answer 22

so...
0^2 is just 0
that means the eqn is:
x^2+y^2=196
done!

Answer 23

you're looking for an equation, not a value :)

Answer 24

oHHHHHHH Lol! Thank youuu I have another radius question! 2nd to last one yay