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OpenStudy (anonymous):
Find the exact value by using a half-angle identity.
sin(5pi/12)
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OpenStudy (anonymous):
help me guys!!!:(
OpenStudy (jtvatsim):
OK, so first of all notice that 5pi/12 is just half of 10pi/12 which is 5pi/6 (that's something we can actually calculate)
OpenStudy (jtvatsim):
We need to use the half angle formula for sin, let me look that up
OpenStudy (jtvatsim):
sin(B/2) = ± sqrt([1 − cos B] / 2)
OpenStudy (jtvatsim):
so sin(5pi/12) = ±sqrt([1 - cos(5pi/6)] / 2)
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OpenStudy (jtvatsim):
= ±sqrt([1 - (sqrt(3)/2)] / 2)
OpenStudy (jtvatsim):
since 5pi/12 is in the first quadrant, we know that sin will be positive so choose the positive value.
OpenStudy (anonymous):
@jtvatsim so is it the same thing as 1/2sqrt(2+sqrt3)?
OpenStudy (jtvatsim):
you got it! :)
OpenStudy (anonymous):
@jtvatsim it wont be 1/2sqrt(2-sqrt3) right??
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OpenStudy (jtvatsim):
correct, that would be the negative answer which we don't want. :)
OpenStudy (jtvatsim):
a good resource to use to look up quick math answers is wolframalpha.com, that's what I used to check.
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