Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

LAST ONE! (:

OpenStudy (anonymous):

OpenStudy (anonymous):

remember the equation: (x-h)^2+(y-k)^2=r^2

OpenStudy (anonymous):

in this case, you do not need the radius like the last one. in this one you need the centre given by (h,k)

OpenStudy (anonymous):

so is h and k 4 and 3?(:

OpenStudy (anonymous):

check the signs

OpenStudy (anonymous):

4 sq. and 3 sq. ? (:

OpenStudy (anonymous):

or is it -4? (: I cant tell but they come out as16 + 9

OpenStudy (anonymous):

no. in the equation (x-h)^2+(y-k)^2=r^2 the centre is (h,k) when it is taken out of the brackets, the sign changes

OpenStudy (anonymous):

you don't need to do any extra work, the answer is already in the equation, you just need to know how to find it

OpenStudy (anonymous):

hmm..so you do something with 2?

OpenStudy (anonymous):

where did the 2 come from?

OpenStudy (anonymous):

oh cause of the sq.? (:

OpenStudy (anonymous):

is it 81?

OpenStudy (anonymous):

cause i did the sq root of 9

OpenStudy (anonymous):

let me see if a diagram wil help... |dw:1360308891504:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!