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Calculate the number of moles of Al2O3 that are produced when 0.60 mol of Fe is produced in the following reaction. 2Al(s)+3FeO(s) -> 3Fe(s)+Al2O3(s) (1point) a.0.20 mol b.0.40 mol c.0.60 mol d.0.90 mol
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the answe is a....use the mole ratio, i.e Fe : AlO3 3 : 1 0.60mol : x solving this equation, it gives 0.20mol of AlO3....
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