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OpenStudy (anonymous):
Verify the identity.
4 csc 2x = 2 csc^2(x) tan x
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OpenStudy (anonymous):
help me!!!!:(
OpenStudy (anonymous):
hi there
OpenStudy (anonymous):
sure simple
OpenStudy (anonymous):
@mathsmind hi!!
OpenStudy (anonymous):
ok now step one
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OpenStudy (anonymous):
okay!
OpenStudy (anonymous):
sin2(x)=2sin(x)cos(x)
OpenStudy (anonymous):
sorry be patient my net is slow
OpenStudy (anonymous):
csc(x) = 1/ sin(x)
OpenStudy (anonymous):
so 4csc(2x) = 4/sin(2x)
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OpenStudy (anonymous):
you agree so far
OpenStudy (anonymous):
4/sin(2x)=2/sin(x)cos(x)
OpenStudy (anonymous):
now am going to use the equation editor to make it clearer for u ok
OpenStudy (anonymous):
we are going to multiply both sides by sin(x)/sin(x)
OpenStudy (anonymous):
okay!!
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OpenStudy (anonymous):
\[=\frac{ 2 }{ \sin(x)\cos(x) }\frac{ \sin(x) }{ \sin(x) }\]
OpenStudy (anonymous):
\[==\frac{ 2 }{ \sin^2(x) }\frac{ \sin(x) }{ \cos(x) }\]
OpenStudy (anonymous):
tan(x) = sin(x)/cos(x), and 2/sin^(x) = 2csc^2(x)
OpenStudy (anonymous):
\[=2 \tan(x)\csc^2(x)\]
OpenStudy (anonymous):
this proves your claim
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OpenStudy (anonymous):
i hope this helped
OpenStudy (anonymous):
are you there?
OpenStudy (anonymous):
thankyou!!!!!!!!!!!!!!!!!!
OpenStudy (anonymous):
you are welcome!
OpenStudy (anonymous):
you need to understand and mesmerism all tig identities like ur name if you don't want to suffer on this topic
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OpenStudy (anonymous):
memorize*
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