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Find the largest number obtainable as the product of positive integers whose sum is 1976.
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Is this a brilliant.org question?
no its not
is it a problem to ask brilliant.org questions on OS
I guess it'd be \(988 \times 988\).
let \[x_1,x_2,....,x_n \space be \space the \space integers \] \[AM \ge GM\] \[\huge \frac{x_1+x_2+...+x_n}{n} \ge \sqrt[n]{x_1x_2...x_n}\] \[\huge \frac{1976^n}{n} \ge x_1x_2...x_n\]
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When you want to find the highest such number, just halve the sum.
denominator n^n
Oh myy...
wats the problem
I am not too good at all those applications . . . I just know that the numbers are \(988\) and \(988\)
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okay i will post the solution but its so much of analysis
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