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Evaluate lim x-> f(x)/g(x) where f(x) = e^2x and g(x) = 3x^2 - 3x + 6
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\[\Large \lim_{x \to ?} \]
lim as x approches ? of\[\frac{e^2x}{3x^2-3x+6}\]
where is the limit directing
lim->1
pretty sure you can just plug in 1 if im not mistaken
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if that was o or infinite then you would have used taylor series to solve it
the only time you need to be fancy with solving limits is if you end up with something like 1/0, 0/0, inf/inf, etc. in this case you can justp lug it in
but since its x->1 then the answer is simple
ok thx guys so i just plug in 1 right?
yup
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ok
I got 3 + e^2/3 ?
should be (e^2)/6 when you plug in 1 in the denominator, the 3x^2 and 3x terms cancel out and you are left with just 6
@funinabox's got this
ok
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