phase shift question
A lightwave travels from point A to B in a vacuum. Suppose we introduce into its path a flast glass plate \(n_g=1.50\) of thickness L=1.00mm. What is the phase shift introduced by the plate?
So I know that the number of wavelengths without the glass is \[N=\frac{d}{\lambda_0}\]and with the glass is \[N'=\frac{d-L}{\lambda}\]where \(d=\overline{AB}\)
so the difference in number of waves, \(D\), is\[D=L\left(\frac{1}{\lambda}-\frac{1}{\lambda_0}\right)\]
I'm lost from here.
ok I guess I could say \[D=L\left(\frac{n-1}{\lambda_0}\right)\]
To work out the phase shift, you need to know the wavelength of your wave in a vacuum. L(n-1) is the difference in optical path. It is to \(\lambda_o\) what your phase shift is to \(2\pi\). So the answer is \(\Delta \phi=2\pi L(n-1)/\lambda_o\) radians
thanks!
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