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Mathematics 7 Online
OpenStudy (anonymous):

5. Find the area of blue portion of the irregular shape to the right. Round your answer to the nearest tenth. 2.7 in² 9.7 in² 3.4 in² 8.3 in²

OpenStudy (anonymous):

OpenStudy (jtvatsim):

think of the question like this... You have a square cookie, and then you take a circular bite out of the middle. The cookie that's left after the bite is the blue area. So, you need to do Area of square - Area of circle = Area of weird shape

OpenStudy (stamp):

\[A_{blue}=A_{square}-A_{circle}\]\[A_{square}=s^2\]\[A_{circle}=\pi r^2\]

OpenStudy (anonymous):

Thats kind of confusing......

OpenStudy (anonymous):

I still cannot figure it out. Please help!

jimthompson5910 (jim_thompson5910):

What do you get for the area of the square?

OpenStudy (anonymous):

I don't know how to get the area of the square because its not telling me the side. I know the radius is 2 and the diameter is 4, but then what? What do i multiply?

jimthompson5910 (jim_thompson5910):

|dw:1360369620399:dw|

jimthompson5910 (jim_thompson5910):

oops it got cut off, it should say side of square = 4

OpenStudy (anonymous):

okay, side of square is 4...... so then do i ultiply it by 2 to get the area, which would be 8?

jimthompson5910 (jim_thompson5910):

no, you square it Area of square = 4^2 = 4*4 = 16 square units

jimthompson5910 (jim_thompson5910):

now use this formula to find the area of the circle A = pi*r^2

OpenStudy (anonymous):

okay so "r" would be 16 right

jimthompson5910 (jim_thompson5910):

r would be 2

jimthompson5910 (jim_thompson5910):

r = radius

OpenStudy (anonymous):

oops.....sorry! I am so bad at this! So is the area 12.56?

jimthompson5910 (jim_thompson5910):

yep

jimthompson5910 (jim_thompson5910):

now subtract the two

OpenStudy (anonymous):

I subtract 12.56 and what?

jimthompson5910 (jim_thompson5910):

that from the area of the square (16)

jimthompson5910 (jim_thompson5910):

Area of square - Area of circle = 16 - 12.56 = ???

OpenStudy (anonymous):

okay so the answer is 3.44

jimthompson5910 (jim_thompson5910):

you got it

jimthompson5910 (jim_thompson5910):

and you round that to get 3.4

OpenStudy (anonymous):

but thats not one of the answer choices.....

jimthompson5910 (jim_thompson5910):

you have to round to the nearest tenth like they want

OpenStudy (anonymous):

o ya sorry!

OpenStudy (anonymous):

forgot that! Can you help me on one more please!

jimthompson5910 (jim_thompson5910):

its fine, besides even if it was off a bit, you can't always get the exact area with an approximation so that's why getting really close is good enough in my book

OpenStudy (anonymous):

3. Find the area for the given circle. Round to the nearest tenth. 113.0 ft² 124.8 ft² 37.7 ft² 452.2 ft²

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

diameter = 12 ft radius = 6 ft (cut the diameter in half)

jimthompson5910 (jim_thompson5910):

so r = 6

OpenStudy (anonymous):

okay so its C = pi x r x 2

jimthompson5910 (jim_thompson5910):

they want the area, not the circumference

jimthompson5910 (jim_thompson5910):

so use A = pi*r^2

OpenStudy (anonymous):

A = 3.14 x 6 x 2 = 113.04?

OpenStudy (anonymous):

when you multiply the two, does it mean to multiply 6 by 6 or 6 by 2

jimthompson5910 (jim_thompson5910):

round to the nearest tenth

OpenStudy (anonymous):

o so its 113.0

jimthompson5910 (jim_thompson5910):

6^2 means that you square 6 so 6^2 = 6*6 = 36

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

okay cool. ummmmmm.... am i wasting ur time or ca i do 2 more? Then i promise thats it!

jimthompson5910 (jim_thompson5910):

you're not as long as you're learning something

OpenStudy (anonymous):

i am finnally getting it i think hold on let me post the problem...

OpenStudy (anonymous):

1. Find the area of the given circle. Round to the nearest tenth. 22.0 cm² 38.5 cm² 11.0 cm² 42.8 cm²

OpenStudy (anonymous):

OpenStudy (anonymous):

A = pi*r^2 = 3.14 x 3.5 x 2

jimthompson5910 (jim_thompson5910):

use ^ instead of x

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