Find cos q if q is an angle in standard position and the point with coordinates (–12, 5) lies on the terminal side of the angle.
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jimthompson5910 (jim_thompson5910):
here is the point (-12,5)
|dw:1360382005873:dw|
jimthompson5910 (jim_thompson5910):
draw a right triangle like so
|dw:1360382048003:dw|
the cosine of angle q will be equal to the cosine of the lower angle on the right side in the triangle
so
cos(q) = adjacent/hypotenuse
cos(q) = -12/13
OpenStudy (anonymous):
How did you find the degree on the unit circle?
OpenStudy (anonymous):
The point* not the degree.
jimthompson5910 (jim_thompson5910):
it's not on the unit circle
if it was, then the hypotenuse would have been 1
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jimthompson5910 (jim_thompson5910):
I'm just using the trig ratios
in this case, cosine = adjacent/hypotenuse
jimthompson5910 (jim_thompson5910):
I guess I should have said that the 13 is from the fact that 5^2 + (-12)^2 = 13^2 by the pythagorean theorem
OpenStudy (anonymous):
oh so pretty much use the formula a^2+b^2=c^2?
jimthompson5910 (jim_thompson5910):
yes to find the missing length of a right triangle
OpenStudy (anonymous):
Ohhh okai thank you c:
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