Help solving:
(9(x^-2)t^6)^(3/2)
all divided by
(27x^5(t^-3))^(2/3)

Question

Help solving: 
(9(x^-2)t^6)^(3/2)
all divided by
(27x^5(t^-3))^(2/3)

anonymous · Answer

Just having trouble with the first step.

chihiroasleaf · Answer

$$\frac{ \left( 9\left( x ^{-2}t ^{6} \right) \right)^{\frac{ 3 }{ 2 }} }{ \left( 27x ^{5}\left( t ^{-3} \right) \right) ^{\frac{ 2 }{ 3 }}}$$

is this your question? 
what are you asking to do? simplify it?

anonymous · Answer

Yes, I have to simplify it.

anonymous · Answer

expand the brackets first
$$(a^mb^n)^p=a^{ m p }b^{ n p}$$

anonymous · Answer

isn't there a way to cancel out the 3/2 and the 2/3?

anonymous · Answer

no, I don't think so

anonymous · Answer

also: remember
$$a^-n=\frac{ 1 }{ a^n }$$

chihiroasleaf · Answer

@ecuddy what do you get from the step that @Chelsea04 said? :)

anonymous · Answer

{(27s^-3 t^9)}/{(9s^(10/3) t^-2)}

anonymous · Answer

|dw:1360414424804:dw|

chihiroasleaf · Answer

why is it become 's' ? :D 

yes... now simplify using the properties
$$\frac{ x ^{m} }{x ^{n} } = x ^{m-n}$$

anonymous · Answer

It was 's' to begin with, I just typed in 'x' by accident. :)

chihiroasleaf · Answer

:lol: ok.., 
so.., what's the result? :)

anonymous · Answer

still working

anonymous · Answer

|dw:1360414940357:dw|

chihiroasleaf · Answer

|dw:1360415020516:dw|