Question

Calculate the amount of heat to be supplied to a system consisting of 100 g of water are 20 ° C for temperature reaches.
a)80° C
b)110° C

Answer 1

Substance Lfusion (J/Kg) Lvapor(J/Kg) c(J/Kg)
ice ----- ---- 2089
water 333*10^3 2,2*10^6 4180
water vapor ------ ----- 1850

Answer 2

@AccessDenied @ataly @Aperez @AccessDenied @Falkqwer @Luis_Rivera @lys1597 @Jonask @jen1511 @ghazi @ghazia @skullpatrol @evergirl

Answer 3

Q = m.s.(t2-t1)
Q-heat supplied or emitted
m-mass
s-specific heat of the substance/liquid/whatever
t1-initial temperature
t2-final temperature

Answer 4

Now, mass m = 100g
specific heat of water s = 1 C/g
initial temp t1 = 20
a) t2 = 80
So, Q = 100x1x(80-20) = 6000 calories

Answer 5

looks good.
@Muskan can you try out the second one with this example?

Answer 6

yup

Answer 7

I was actually typing the solution to the second one to, but ya I'd love to see you do it too.

Answer 8

and in the end, if it can be done collaboratively that would be cool!

Answer 9

Remember at 0degrees and 100degrees, without a change in temp, heat is either absorbed or emitted according to the direction of the cycle.

Answer 10

ok

Answer 11

Lol no need to tag me. I dont understand math whatsoever.