Question

please can anyone help me ? Write the sum using summation notation, assuming the suggested pattern continues.
-10 - 2 + 6 + 14 + ... + 110

Answer 1

\[d=8, a _{n}=110 \]
\[a _{n}=a _{1} +d(n-1)\]
\[a _{1}=-10 \]
110=-10+8(n-1)
120=8(n-1)
n-1=15
n=16

Answer 2

110 is 16th term

Answer 3

ima show you my answer choices

Answer 4

\[_{Sn}=\frac{ n }{ 2 }(2a _{1}+(n-1)d)\]
then substitute the above values
\[S _{16}=8(-10+110)=8*100=800\]

Answer 5

the answer is 800

Answer 6

\[\sum_{n=0}^{15}(-10+8n) \sum_{n=0}^{\infty}(-10+8n) \sum_{n=0}^{15}-80n \sum_{n=0}^{\infty}-80n\]

Answer 7

@getusel which one would be the choice ?

Answer 8

the first one is right

Answer 9

thanks

Answer 10

\[\sum_{0}^{15}(-10+8n)\]

Answer 11

it is my pleasure

Answer 12

@getusel i have another problem im trying to solve