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Physics 20 Online
OpenStudy (anonymous):

How should i go about finding the desired velocity for a satellite to orbit mars in a given time.

OpenStudy (anonymous):

time=115646.459s mmars = 6.4191 x 10^23 kg rmars = 3.397 x 10^6 m G = 6.67428 x 10^-11 N-m2/kg2

OpenStudy (anonymous):

at a velocity of 2650 m/s: radius of motion (from center of planet) = 6096890m force of attraction = 4149 acceleration = 1.153

OpenStudy (goformit100):

you can do so by knowing it's RPM.

OpenStudy (anonymous):

then i need to know the radius, and the radius is a function of the gravitational attraction witch is also a fucntion of acceleration which is a function of velocity, ahh!

OpenStudy (anonymous):

\[r=(\frac{ mGt }{ 2\pi })^{2/3},v=\frac{\sqrt( mG )}{ \sqrt(r) }\] here is the solution in case anyone is having the same problem

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