Question

solve equation write mathematical model representing the monthly cost, C, there are two options, let x=hours per month of court rental time #1, option35$ monthly fee plus $4hour for court rental#2 option, no monthly fee but $6.50hour/hour for court rental

Answer 1

solve equation write mathematical model representing the monthly cost, C, there are two options, let x=hours per month of court rental time #1, option35$ monthly fee plus $4hour for court rental#2 option, no monthly fee but $6.50hour/hour for court rental how many rentals is option1 less than option2

Answer 2

my full question in attachment so you can get better understanding

Answer 3

Were you able to find any of the equations?

Answer 4

no can u look at the attachment

Answer 5

the option1 and2 is whati need help on

Answer 6

ok if x = hours per month of court rental time and C = total cost per month

then the first equation is C = 4x + 35

Why? because if you rent the court for x hours, then you pay $4 an hour, and you pay 4x total...but you also pay the fixed monthly fee on top of that which is $35

So you pay a total of 4x+35 dollars which is why the first equation is C = 4x + 35

Answer 7

the second option is no monthly fee, so the second equation is just C = 6.5x

Answer 8

So we have

C = 4x + 35
C = 6.5x

Set them equal to each other to get

6.5x = 4x + 35

Now solve for x

Answer 9

does that make sense?

Answer 10

yes

Answer 11

ok great

Answer 12

now do i have to distribute the like terms

Answer 13

6.5x = 4x + 35

6.5x - 4x = 35 ... Subtract 4x from both sides.

Keep going

Answer 14

31[6.5

Answer 15

4

Answer 16

6.5x = 4x + 35

6.5x - 4x = 35

2.5x = 35

x = 35/2.5

x = 14

Answer 17

This means that the two costs will be the same when you rent the court for 14 hours total in a month

Answer 18

Anything past 14 hours will make the second plan (the one without the monthly fee) more expensive

Answer 19

Anything below 14 hours will make the first plan (with the monthly fee) more expensive

Answer 20

okay thanku

Answer 21

np

Answer 22

yes

Answer 23

now working on another

Answer 24

alright

Answer 25

this is what i am working on now and is clueless

Answer 26

have you gotten started at all?

Answer 27

yes but still confused

Answer 28

the base is 3
oflog35=y
loga7=-2=a-2=7

Answer 29

\[\Large \log_{3}(5) = y\]

is the same as

\[\Large 3^y = 5\]

using the rule provided in the pdf

Answer 30

\[\Large \log_{a}(7) = -2\]

is the same as

\[\Large a^{-2} = 7\]

using the rule provided in the pdf

and you're doing that with the rest

Answer 31

no because it say solve

Answer 32

for partb

Answer 33

you would use the rule used in part a to isolate the variable

Answer 34

ok

Answer 35

so log2x-3

Answer 36

that would turn into

x = 2^(-3)

x = 1/(2^3)

x = 1/8

Answer 37

so logx9=1/2=x=1/2(9)

Answer 38

1/2

Answer 39

or x=1/(9^1/2)=2/1

Answer 40

x = 9^(1/2)

x = sqrt(9)

x = ???

Answer 41

81

Answer 42

the square root of 9

NOT 9 squared

Answer 43

ok,3

Answer 44

yep

Answer 45

for 2 the graph it would be 10 left1 right

Answer 46

\[\Large e^{x}+2\] shifts the entire graph up 2 units

Answer 47

ok

Answer 48

hx=-ex=0

Answer 49

sticking a negative on e^x flips the graph over the x-axis

Answer 50

so it would be-e^x

Answer 51

yeah

Answer 52

for3a do i just add

Answer 53

you plug in x = 5 and evaluate

Answer 54

not sure done right i got112

Answer 55

way too high

Answer 56

ok

Answer 57

-3=12-20+5=-3

Answer 58

do you have a calculator?

Answer 59

not working

Answer 60

use google as a calculator then

http://www.google.com/search?hl=&q=12%2B20*ln%285%29&sourceid=navclient-ff&rlz=1B3GGLL_enUS420US420&ie=UTF-8

Answer 61

ok so i have to plug inp=12+20/5

Answer 62

ok thanks so it would be the same equation but would have to multiply6

Answer 63

44. 1887582487 but have to round to six decimals so it would be 50

Answer 64

it would be 44.188758 after rounding

Answer 65

ok

Answer 66

if ,i were to add 2002+2005=4007, but how would i begin to solve for 2005

Answer 67

why are you adding 2002 to 2005 ?

Answer 68

i thought i have to

Answer 69

no you don't, I'm not exactly sure what you're doing

Answer 70

me either but trying to solve for2005

Answer 71

you're not solving for 2005, you're plugging in x =5 and evaluating

Answer 72

12+20xin5=44.18 round two decimals

Answer 73

it's Ln not in, and you should have it rounded to 6 decimal places

Answer 74

44.188758

Answer 75

yes

Answer 76

okay

Answer 77

so if i have to round it to more decimals it would be44.288758

Answer 78

just leave it at 44.188758 and that's fine

Answer 79

ok

Answer 80

b, would be 90%=0.9

Answer 81

solve

12+20*ln(x) = 90

for x

Answer 82

ok

Answer 83

can i use 10 or just1 in the model?

Answer 84

what do you mean 10?

Answer 85

90 then idid 12+20*Ln(90)=101.996193407

Answer 86

okay, i just use 1

Answer 87

no you solve 12+20*ln(x) = 90 for x

Answer 88

you don't plug in 90 for x

Answer 89

ok

Answer 90

14

Answer 91

12+20*Ln(-8)=90

Answer 92

12+20*ln(x) = 90

20*ln(x) = 90-12

20*ln(x) = 78

ln(x) = 78/20

ln(x) = 3.9

x = ???

Answer 93

78

Answer 94

78/20=3.9=x

Answer 95

12

Answer 96

because x=90

Answer 97

3900 because i have to round 2 decimals