Question

Can someone please check to see if my answer is correct please.
Solve for x
84e^1.02x=25

Answer 1

what answer did you get?

Answer 2

I got 10.56 I'm not sure if this right

Answer 3

hmmm. .. so you have this equation right?
\[84e^{1.02x} = 25\]

Answer 4

yes

Answer 5

OK, you can always check if your answer is right just by plugging it back in so
\[84e^{1.02\cdot 10.56}=25\]
\[84e^{10.7712} = 25\]
\[4000847.609=25\]
so the answer doesn't work

Answer 6

This is how I solved it:

Answer 7

\[84e^{1.02x}=25\]
\[e^{1.02x}=\frac{25}{84}\]
\[1.02x=\ln(\frac{25}{84})\]
\[x=\frac{1}{1.02}\ln(\frac{25}{84}) \approx -1.1881\]

Answer 8

Oh I did'nt type the ln over 25/84 right. so now I got -1.1881 is that correct

Answer 9

yep, you've got it! :D

Answer 10

thank you

Answer 11

yw