How would you do integral (cosx/(ln(x+1))dx?
Just for anyone else, the integral is: \[\int\limits \frac{ \cos x }{ \ln(x+1) } dx\]
\[\int\limits \frac{ \cos x }{ \ln(x+1) }dx\]
Moving onto actually solving it.
-_- i'm too slow just fyi, no trig sub or integration by parts
Hmm then how are you suppose to approach this one? Wolfram didn't come up with a solution. Does this involve Power Series or something? :o
@zepdrix, it is possible, let me figure it out.
But do you know?
@Zelda , please erase your previous comment, and don't talk so vulgar on here... :(
No I don't know how to do this one I'm afraid :c
Sorry, just got frustrated, noticed that 3/4ths in.
I'm fairly certain there's no closed form solution.
It's actually possible. But requires a power series. @jennychan12, is that okay? Using a power series?
what is that? sorry. i'm not good with names. but i think i learned it? is it the same as power rule or something like that?
No, not a power rule. http://en.wikipedia.org/wiki/Power_series BTW, what level calc are you in?
calc Ab
So I'm assuming you haven't learned the taylor series then?
no... -_- what. my teacher gave me ANOTHER BC question. er...something i haven't learned yet. *sigh* my teacher should really make her own practice tests...
Yea, she did. Would you still like to know how? Also, this actually goes into Calc III a bit, not even BC fully explores series.
Not sure, but I highly doubt it has an elementary anti-derivative.
uhh. i would, but i have a quiz on monday and i don't wanna learn new stuff that my teacher hasn't really taught yet.
@wio, it actually doesn't. You need a power series to integrate it.
@jennychan12, in that case I won't go over it. Just say it's impossible since it has no elementary anti-derivative
ok haha ok.
thanks for your help tho! @Zelda :)
@jennychan12, no prob. If you want it done later I can show you how.
nahh, not now. my brain might explode. haha :/
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